5x^2=92x

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Solution for 5x^2=92x equation:



5x^2=92x
We move all terms to the left:
5x^2-(92x)=0
a = 5; b = -92; c = 0;
Δ = b2-4ac
Δ = -922-4·5·0
Δ = 8464
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8464}=92$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-92)-92}{2*5}=\frac{0}{10} =0 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-92)+92}{2*5}=\frac{184}{10} =18+2/5 $

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